-32x^2-8x+4=0

Solution for -32x^2-8x+4=0 equation:

-32x^2-8x+4=0

a = -32; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·(-32)·4
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-24}{2*-32}=\frac{-16}{-64}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+24}{2*-32}=\frac{32}{-64}
=-1/2
$